Quote:
Originally Posted by guest001
another thing that I don't understand is, the pressure inside the cylinder before the plug is ignited is relatively low. when it does ignite and starts to burn, the pressure starts to climb right immediately. so wouldn't that pressure start to push to piston down, even before TDC?? or is force, forcing the piston up is so great, even the peak pressure wouldn't stop it right then?
so, the peak happening at that 90 degree angle, if it happens any where else the total force applied to the crank during the combustion stroke would be less?
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The pressure does start to climb immediately after spark, however the upward force exerted by the other cylinders is far more than enough to keep it from trying to stop. And while the 10-15 degrees of burn between spark and TDC are technically wasted, that is also at the low end of the pressure cycle of burn, so you waste the early, light pressure so that you can better capture the mid burn, high pressure stuff.
If the spark happens at TDC, while you're capturing the early burn pressure that would have been wasted, the real strong stuff about halfway through the burn would be right near the end of the power stroke, and pretty much wasted.
The second question... The total force applied to the crank would be the same, however, with the rod being at 90* to the crank/rod journal lever, that's where most of the force is converted to rotational torque and spinning the crank, rather than the pressure passing through the crank to the main journals and being turned into vibration.
Like if you take a wrench, and turn it with some set force, you spin the nut. However, if you were to put the wrench on the nut and instead of applying the force perpendicular to the wrench, you apply the force in line with the wrench, you'd just transmit the force directly to the nut in a futile pushing manner. Same basic thing.
Technically with the adjusted ignition timing, the total force wouldn't be identical, what with some burn pressure being wasted near the top of the compression stroke, or if it's too late of an ignition, some burn pressure still occurring in the exhaust stroke... But that doesn't matter with the question we're dealing with.
It all boils down that the forces will be the same, however with properly tuned ignition timing, more of that force will be converted into work (rotational force), rather than waste vibration.
Edit: As I forgot to answer one of your earlier questions...
No, if the peak pressure ends up occurring during the compression stroke, that won't stop the pistons... It'll break them. That's called Detonation, and it usually occurs because the mix is too lean, so that little amount of gas just burns right up, very fast. It usually ends up doing nasty things like blowing head gaskets, breaking holes in pistons, and otherwise doing very bad things to the engine.
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