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Originally Posted by theholycow
Those tires will need more pressure than the existing tires.
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Why? I am running my existing tires over the recommended pressure anyway. i plan to do the same with the new ones.
Quote:
Originally Posted by theholycow
Also, don't forget that the odometer will suffer from the same change in accuracy that the speedometer does, so calculate that in to your FE calculations.
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I mentioned in my post that the vehicles velocity would change. I am currently adding 2.1% to my mileage because the OE tire for my car would have been a 185/60/14. For the new tires I will be subtracting 0.4%
Quote:
Originally Posted by theholycow
I am skeptical about the rotating weight issue. Based on the science that I know about it and the words of experts in other contexts, I believe that it's a myth.
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From an engineers perspective, in a vacuum, it would take no extra energy to maintain the velocity of a larger mass than a smaller one. But accelerating the mass is where energy can be saved. It would consume less energy to accelerate to speed from every stop.
So if you did an A-B-A with a scangauge and started the measurements when you were allready at cruising speed then you would see no improvement. BUT, if you consider the full mileage covered by a full tank (like I do) then you should see more of a difference. That is why racers use lighter wheels, because less energy goes to accelerating the rotating mass and more energy goes into accelerating the vehicle.
If less energy is needed to drive the same way that I allready do, then less throttle would be applied and less fuel burned.
Quote:
Originally Posted by bobc455
Decreasing rotating weight won't help much, unless you are drag racing where increasing rotational inertia sucks energy away from increasing your forward speed.
However reciprocating mass (pistons, valves, etc.) do "suck" energy to move.
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That seems to contradict itself and confirmmy argument. If less energy is lost to rotational inertia then less energy is required to accelerate the vehicle (assuming you are not trying to accelerate harder like a drag racer would be). So for stop and go driving, a vehicle with less rotational mass would be more efficient right?
I contend that if every other parameter was maintained equal, and a vehicles rotating parts were replaced with lighter weight materials (from the crank pulley, through the drivetrain, all the way to the tires) that the vehicle would be more efficient.
I am assuming of course that techniques like P&G are not used because that in fact requires rotational inertia to extract energy back out of on the glide. My assumption is for the standard American driver or for people like myself who accelerate normally through the gears and use cruise control often.
And Ford Man, I mentioned in my orginal post that to maintain the same vehicle speed (69.03mph, my car would change from 3200rpm now to 3281rpm with smaller tires) but I don't think 81rpm will consume significantly more fuel. i am considering a transmission change in the future however that would bring the rpms below stock at cruising speed.
Sorry for the long post, and I am very open to criticism or correction because that seems to be the best way to learn.
-Tony